5(x+2)^1/2=27

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Solution for 5(x+2)^1/2=27 equation: 



5(x+2)^1/2=27

We move all terms to the left:

5(x+2)^1/2-(27)=0

We multiply all the terms by the denominator


5(x+2)^1-27*2=0

We add all the numbers together, and all the variables

5(x+2)^1-54=0

We move all terms containing x to the left, all other terms to the right

5(x+2)^1=54

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